x^2-2x-125=0

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Solution for x^2-2x-125=0 equation:


Simplifying
x2 + -2x + -125 = 0

Reorder the terms:
-125 + -2x + x2 = 0

Solving
-125 + -2x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '125' to each side of the equation.
-125 + -2x + 125 + x2 = 0 + 125

Reorder the terms:
-125 + 125 + -2x + x2 = 0 + 125

Combine like terms: -125 + 125 = 0
0 + -2x + x2 = 0 + 125
-2x + x2 = 0 + 125

Combine like terms: 0 + 125 = 125
-2x + x2 = 125

The x term is -2x.  Take half its coefficient (-1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
-2x + 1 + x2 = 125 + 1

Reorder the terms:
1 + -2x + x2 = 125 + 1

Combine like terms: 125 + 1 = 126
1 + -2x + x2 = 126

Factor a perfect square on the left side:
(x + -1)(x + -1) = 126

Calculate the square root of the right side: 11.22497216

Break this problem into two subproblems by setting 
(x + -1) equal to 11.22497216 and -11.22497216.

Subproblem 1

x + -1 = 11.22497216 Simplifying x + -1 = 11.22497216 Reorder the terms: -1 + x = 11.22497216 Solving -1 + x = 11.22497216 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '1' to each side of the equation. -1 + 1 + x = 11.22497216 + 1 Combine like terms: -1 + 1 = 0 0 + x = 11.22497216 + 1 x = 11.22497216 + 1 Combine like terms: 11.22497216 + 1 = 12.22497216 x = 12.22497216 Simplifying x = 12.22497216

Subproblem 2

x + -1 = -11.22497216 Simplifying x + -1 = -11.22497216 Reorder the terms: -1 + x = -11.22497216 Solving -1 + x = -11.22497216 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '1' to each side of the equation. -1 + 1 + x = -11.22497216 + 1 Combine like terms: -1 + 1 = 0 0 + x = -11.22497216 + 1 x = -11.22497216 + 1 Combine like terms: -11.22497216 + 1 = -10.22497216 x = -10.22497216 Simplifying x = -10.22497216

Solution

The solution to the problem is based on the solutions from the subproblems. x = {12.22497216, -10.22497216}

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